SOLUTION: find four consecutive odd integers if twice the fourth is 119 less than the sum of the first three

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Question 1053252: find four consecutive odd integers if twice the fourth is 119 less than the sum of the first three
Answer by Boreal(15235) About Me  (Show Source):
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the integers are x, x+2,x+4, and x+6
the sum of the first 3 is 3x+6
2(x+6)+119=3x+6. That is another way to say twice the fourth is 119 less than the sum of the first three.
2x+12+119=3x+6
x=12+119-6=125
the integers are 125,127,129, and 131. They are odd. ANSWER
twice 131 is 262, and that is 119 less than 381, the sum of the other 3.