SOLUTION: The height h in feet of a Frisbee thrown is given by h(x)=x-0.099x^2+3, where x is the time traveled in seconds. The Frisbee is released at a height of 3 feet. At what time will

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The height h in feet of a Frisbee thrown is given by h(x)=x-0.099x^2+3, where x is the time traveled in seconds. The Frisbee is released at a height of 3 feet. At what time will       Log On


   

Question 1053227: The height h in feet of a Frisbee thrown is given by h(x)=x-0.099x^2+3, where x is the time traveled in seconds. The Frisbee is released at a height of 3 feet. At what time will the height of the Frisbee be 3 feet again?
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The height h in feet of a Frisbee thrown is given by h(x)=x-0.099x^2+3, where x is the time traveled in seconds. The Frisbee is released at a height of 3 feet. At what time will the height of the Frisbee be 3 feet again?
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When h(x) = 3
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h(x)=x-0.099x^2+3 = 3
x - 0.099x^2 + 3 = 3
It's a quadratic.
Solve for x.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
h(x)=x-0.099x^2+3
3 = x-0.099x^2+3
0 = x-0.099x^2
0 =x(1-.099x)
1 = .099x
x = 1/.099 = 10.1 sec