SOLUTION: an aircraft carrier left hawaii and traveled toward dry dock at an average speed of 25.4 mph. a fishing boat left at the same time and traveled the opposite direction with an avera

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: an aircraft carrier left hawaii and traveled toward dry dock at an average speed of 25.4 mph. a fishing boat left at the same time and traveled the opposite direction with an avera      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1053184: an aircraft carrier left hawaii and traveled toward dry dock at an average speed of 25.4 mph. a fishing boat left at the same time and traveled the opposite direction with an average speed of 26.5 mph. how long does the fishing boat need to travel before the vessels are 622.8 mi apart
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I don't quite get the " how long " part. Is that
time or distance they want? I'll give you both
----------------------------------------
Let +t+ = time in hrs for them to be +622.8+ mi apart
Let +d+ = the distance in miles the fishing boat travels in time +t+
----------------------
Equation for fishing boat:
(1) +d+=+26.5t+
Equation for aircraft carrier:
(2) +622.8+-+d+=+25.4t+
-------------------------
Plug (1) into (2)
(2) +622.8+-+26.5t+=+25.4t+
(2) +51.9t+=+622.8+
(2) +t+=+12+ hrs
-------------------------
Plug this result back into (1)
(1) +d+=+26.5%2A12+
(1) +d+=+318+ mi
-------------------------
So , the fishing boat takes 12 hrs
to travel 318 mi at which time they are
622.8 mi apart
---------------
check answer:
(2) +622.8+-+d+=+25.4t+
(2) +622.8+-+318+=+25.4t+
(2) +25.4t+=+304.8+
(2) +t+=+12+
OK