SOLUTION: The set {(x,y)}|x=0
The domain of the functioned defined by f(x)=√3-x is the set of non_negative real numbers
If f(x)=4-2x+x^2, then f(1-a)=a^2+3
If f(x)=√(1/2)x^2-x
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-> SOLUTION: The set {(x,y)}|x=0
The domain of the functioned defined by f(x)=√3-x is the set of non_negative real numbers
If f(x)=4-2x+x^2, then f(1-a)=a^2+3
If f(x)=√(1/2)x^2-x
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Question 1053012: The set {(x,y)}|x=0
The domain of the functioned defined by f(x)=√3-x is the set of non_negative real numbers
If f(x)=4-2x+x^2, then f(1-a)=a^2+3
If f(x)=√(1/2)x^2-x, then f(-2)=0
The range of the function defined by f(x)=√-x Answer by ikleyn(52794) (Show Source):
