SOLUTION: Find the exact solution to the exponential equation 21=24(0.6)^q

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Question 1052892: Find the exact solution to the exponential equation 21=24(0.6)^q
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
21=24(0.6)^q
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0.6^q = 21/24
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q*log(0.6) = log(21/24)
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q = log(21/24)/log(0.6)
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q = 0.2614
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Cheers,
Stan H.
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