SOLUTION: Please help me with this: Mimi joined a basketball team since summer 2016. On average, she is able to score 30% of the field goals. Assume she tries 15 field goals in a game.

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Question 1052851: Please help me with this:
Mimi joined a basketball team since summer 2016. On average, she is able to score 30%
of the field goals. Assume she tries 15 field goals in a game.
(a) Let X be the number of field goals that Mimi scores in the game. As we know, the distribution of X is a binomial probability distribution. What is the number of trials (n), probability of successes (p) and probability of failures (q), respectively?
(b) Find the probability that Mimi scores at least 2 of the 15 field goals. (round the answer to 3 decimal places) Please show all work.
I really appreciate your help!

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
a) p = .30, q = .70 , n = 15
b) P(x >=2) =1 - binomcdf(15, .30, 1)
Or
P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+
P(x >=2) = 1 - P(0) - P(1) = 1 - 15C0(.70^3) - 15C1(.70)^2(.30)^1