Hi
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) Count them... 36 ways...3 qualify
(a) What is the probability that the sum of the two rolls is at least 10 given that the first one is a multiple of 3? 3/36 = 1/12
(b) Are event A and event B independent? Each roll of the Dice is Independent of the Other.
As to event A and event B being independent:
A the event that the sum of the two rolls is at least 10,
and B the event that the first one is a multiple of 3.
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Event A is dependent on the restraints of Event B