SOLUTION: Workout the gradient and turning point p (x, y) of the curve y=ax^2+bx+c.use the turning point p (x, y) to find the turning point of the curve y=-2x^2-2x+3

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Question 1052785: Workout the gradient and turning point p (x, y) of the curve y=ax^2+bx+c.use the turning point p (x, y) to find the turning point of the curve y=-2x^2-2x+3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Covert the equation to vertex form,
y=ax%5E2%2Bbx%2Bc
y=a%28x%5E2%2B%28b%2Fa%29x%29%2Bc
y=a%28x%5E2%2B%28b%2Fa%29x%2B%28b%2F%282a%29%29%5E2%29%2Bc-a%28b%2F%282a%29%29%5E2
y=a%28x%2B%28b%2F%282a%29%29%29%5E2%2B%28c-b%5E2%2F%284a%29%29
So then the vertex(turning point) is
(-b%2F%282a%29,c-b%5E2%2F%284a%29)
So then for the example,
a=-2
b=-2
c=3
The turning point would be,
(-%28-2%2F%282%28-2%29%29%29,3-%28-2%29%5E2%2F%284%28-2%29%29)
(-1%2F2,7%2F2)