SOLUTION: The length of a rectangle is 2 cm longer than its width. If the perimeter of the rectangle is 28 cm, find its area
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Question 1052491: The length of a rectangle is 2 cm longer than its width. If the perimeter of the rectangle is 28 cm, find its area Answer by ikleyn(52785) (Show Source):
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The length of a rectangle is 2 cm longer than its width. If the perimeter of the rectangle is 28 cm, find its area
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Let W = the width.
Then the length = W+2.
The perimeter is
2W + 2(W+2) = 28,
4W + 4 = 28 ---> 4W = 28-4 ---> 4W = 24 ---> W = = 6.
Answer. The dimensions are 6 and 8. The area is 6*8 = 48 .
