SOLUTION: An airplane takes off from an airport at 7:00 a.m. traveling at a rate of 350 mph. Two hours later, a jet takes off from the same airport following the same flight path at 490 mph.

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Question 1052251: An airplane takes off from an airport at 7:00 a.m. traveling at a rate of 350 mph. Two hours later, a jet takes off from the same airport following the same flight path at 490 mph. How many hours will it take the jet to catch up with airplane?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
The two travelers/vehicles catchup problem 

                 SPEED           TIME           DISTANCE
EARLYSLOW        350             t+2             d
LATEFAST         490             t               d


Basic Rule RT=D;
solve for both d and t;
Concentrate on time quantities first, and time points later.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
An airplane takes off from an airport at 7:00 a.m. traveling at a rate of 350 mph. Two hours later, a jet takes off from the same airport following the same flight path at 490 mph. How many hours will it take the jet to catch up with airplane?
Let time taken by jet to get to meetup point, be T

Then time taken by airplane to get to meetup point = T + 2

We then get the following DISTANCE equation: 490T = 350(T + 2)

Solve this for T, the time the jet took to catch up with the airplane. You should get: highlight_green%28matrix%281%2C2%2C+5%2C+hours%29%29

It's that simple.....nothing complex!