SOLUTION: Find three consecutive odd integers with the property that 3 times the first integer plus twice the second integer is 5 more than twice the third integer

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Question 1052151: Find three consecutive odd integers with the property that 3 times the first integer plus twice the second integer is 5 more than twice the third integer
Found 2 solutions by ewatrrr, advanced_Learner:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
three consecutive odd integers x , (x+2), (x+4)
3x + 2(x+2) = 2(x+4) + 5
3x + 2x + 4 = 2x + 8 + 5
3x = 9
x = 3
three consecutive odd integers: 3, 5, 7
checking
9 + 10 = 14 + 5 CHECKS!

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!

let x-2,x,x+2 be the odd consecutive integers.
3%28x-2%29+2%28x%29=2%28x%2B2%29+%285%29
%283x-6%29+%282x%29=%282x%2B4%29+%285%29
%283x-6%29=%284%29+%285%29
%283x%29=%2810%29+%285%29
%28x%29=%2815%2F3%29
%28x%29=%285%29
the numbers are 3,5,7
check
3(3)+2(5)=5+14
19=19