SOLUTION: Find two consecutive odd integers such that 40 more than the lesser is three times the greater

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Question 1052147: Find two consecutive odd integers such that 40 more than the lesser is three times the greater
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
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Find two consecutive odd integers such that 40 more than the lesser is three times the greater
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Use n-2 & n
n-2 + 40 = 3n
2n = 38
n = 19
--> 17 & 19

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Answer. 17 and 19.


n+40 = 3(n+2),
n + 40 = 3n + 6,
2n = 40 - 6 = 34,
n = 34%2F2 = 17.