SOLUTION: A word problem is expressed as 3(2n+1)=2(2n+3)+5.
This implies 6n+3=4n+6+5. The next step given as the solution eludes me as to how they came up with it. How does that turn into
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-> SOLUTION: A word problem is expressed as 3(2n+1)=2(2n+3)+5.
This implies 6n+3=4n+6+5. The next step given as the solution eludes me as to how they came up with it. How does that turn into
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Question 1052103: A word problem is expressed as 3(2n+1)=2(2n+3)+5.
This implies 6n+3=4n+6+5. The next step given as the solution eludes me as to how they came up with it. How does that turn into 2n=8 (and thus n=4)? I would appreciate an explanation here. Thank you! Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! The equation looks like it comes from consecutive odd integers. Three times the first odd integer is five more than two times the next odd integer. Find n and you can evaluate the two integers.
, distributive property; , maybe a step you should have seen to do but did not;
You can put this solution on YOUR website!
A word problem is expressed as 3(2n+1)=2(2n+3)+5.
This implies 6n+3=4n+6+5. The next step given as the solution eludes me as to how they came up with it. How does that turn into 2n=8 (and thus n=4)? I would appreciate an explanation here. Thank you!
3(2n + 1) = 2(2n + 3) + 5
6n + 3 = 4n + 6 + 5 <==== This is where you are
6n + 3 = 4n + 11 -------- COMBINING like-terms + 6 and + 5 on right side
- 4n - 4n ------------- Subtracting 4n from both sides in order to MOVE 4n to left side of equals sign, and subsequently ISOLATE n
2n + 3 = 11
- 3 - 3 ------------- Subtracting 3 from both sides in order to MOVE 3 to right side of equals sign
2n = 8
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