SOLUTION: Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many
Log On
Question 1051843: Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many did each have at first.
thanks Found 3 solutions by josgarithmetic, MathTherapy, advanced_Learner:Answer by josgarithmetic(39618) (Show Source):
ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken.
Simplify each equation.
-
-
* -------------MISTAKE HERE! Ruins the rest of the work.
-
Substitute for x.
Solve this for y. ---------------This makes no sense. y would be negative.
* MISTAKE IDENTIFIED; solution process not yet corrected
You can put this solution on YOUR website!
Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many did each have at first.
thanks
You can put this solution on YOUR website! Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many did each have at first.
thanks