SOLUTION: a. x^3+9 b. When using long division, what binomial would you divide by to determine if -1 is a zero for your polynomial? c. Do the long division you just described in part b. S

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: a. x^3+9 b. When using long division, what binomial would you divide by to determine if -1 is a zero for your polynomial? c. Do the long division you just described in part b. S      Log On


   



Question 1051773: a. x^3+9
b. When using long division, what binomial would you divide by to determine if -1 is a zero for your polynomial?
c. Do the long division you just described in part b. Show all your work.
d. Is -1 a zero? Explain how you can tell from the long division work.



Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
If -1 is a 0, then x+1 is the binomial, because x=1=0, and x=-1
=======x^2
x-1/x^3+0x^2+0x+9
====x^3-x^2
change signs and subtract
======-x
x-1/-x^2+0x+9
====-x^2+x
change signs and subtract
=====-x +9
x-1 does not divide evenly into -x+9, so -1 is not a 0.
f(-1)=-1+9=8, which is not 0.
graph confirms that:graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3%2B9%29
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