Question 1051771: A bag of coins contains nickels, dimes, and quarters. There are a total of 61 coins in the bag, and the total amount of money in the bag is $7.70. There are three more dimes than quarters. How many dimes, nickels, and quarters are in
the bag?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! n+d+q=61, the equation of the count of coins.
but d-3=q
n+d+d-3=n+2d-3=61;n+2d=64
.05n+.1d+.25(d-3)=7.70, the equation of the value of the coins
.05n+.35d-0.75=7.70, after distributing
.05n+.35d=8.45, after collecting terms
n+2d=64
multiply the first by -20
-n-7d=-169
n+2d=64
-5d=-105
d=21
21 dimes
18 quarters
61-39=22 nickels
That is $2.10+$4.50+$1.10=$7.70 checks
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