SOLUTION: Systems of Equations in three variables x-4y+3z=-27 2x+2y-3z=22 4z-=-16

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Question 1051757: Systems of Equations in three variables
x-4y+3z=-27
2x+2y-3z=22
4z-=-16
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
From eq. 3,
z=-4
Substitute into eq. 1 and eq. 2,
x-4y%2B3%28-4%29=-27
3.x-4y=-15
and
2x%2B2y-3%28-4%29=22
2x%2B2y=10
4.x%2By=5
Subtract eq. 4 from eq. 3,
x-4y-x-y=-15-5
-5y=-20
y=4
So then,
x%2B4=5
x=1
So,
(x,y,z)=(1,4,-4)