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A rectangular piece of land whose length is twice its width has a diagonal distance of 5555 yards. How many​ yards, to the nearest tenth of a​ yard, does a person sav
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A rectangular piece of land whose length is twice its width has a diagonal distance of 5555 yards. How many​ yards, to the nearest tenth of a​ yard, does a person sav
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Question 1051612:
A rectangular piece of land whose length is twice its width has a diagonal distance of 5555 yards. How many yards, to the nearest tenth of a yard, does a person save by walking diagonally across the land instead of walking its length and its width? Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let w be the width of the triangle. Then the length would be 2w. So:
w²+(2w)²=5555²
5w²=(5555)²
w²=6171605
w=2484.27,-2484.27
l=4968.54
w+l=7452..81
7452.81-5555=1897.81 yards saved by walking diagonally. ☺☺☺☺
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