SOLUTION: find the lenghts of the missing sides of the triangles. First triangle side 1 = 10, side 2=6, side 3=a Second triangle side 1 = 14, side 2 = b, side 3=11.2 I have no idea

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Question 105123: find the lenghts of the missing sides of the triangles.
First triangle side 1 = 10, side 2=6, side 3=a
Second triangle side 1 = 14, side 2 = b, side 3=11.2
I have no idea how to do this. Please help.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Pythagoras' Theorem claims that a2+%2B+b2+=+c2 where c is the hypotenuse while a and b are the legs of the triangle.
First triangle:
side 1 = c+=+10
side 2 = b+=+6+
side 3=a
then:
10%5E2+=+a%5E2+%2B+6%5E2
100+=+a%5E2+%2B+36
100+%96+36+=+a%5E2
64+=+a%5E2
a+=+sqrt%2864%29
a+=+8

Second triangle:

side 1 = c+=+14
side 2=+b
side 3 = a+=+11.2
then we will have:

14%5E2+=+%2811.2%29%5E2+%2B+b%5E2
196+=+125.44+%2B+b%5E2
+196+-+125.44+=+b%5E2
b%5E2+=+70.56
b+=+sqrt%2870.56%29
b+=+8.4