SOLUTION: [(x^2)-4x+7]log 5 + log 16 = 4 I need to know x.

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Question 1050838: [(x^2)-4x+7]log 5 + log 16 = 4
I need to know x.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
[(x^2)-4x+7]log 5 + log 16 = 4
I need to know x.
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x^2-4x+7 = (4 - log(16))/log(5) = log(10000/16)/log(5) = log(625)/log(5) = 4
x^2 - 4x + 3 = 0
(x-1)*(x-3) = 0
x = 1
x = 3