SOLUTION: The distance between Toronto and Ottawa is 350 km. A train leaves each station and the train leaving Ottawa is 10 km/h faster then the train leaving toronto. They meet after 2.5

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Question 1050751: The distance between Toronto and Ottawa is 350 km. A train leaves each station and the train leaving Ottawa is 10 km/h faster then the train leaving toronto. They meet after 2.5 hours how fast is each train travelling?
Found 2 solutions by josmiceli, advanced_Learner:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ =the speed of T to O train in km/hr
+s+%2B+10+ = the speed of the O to T train in km/hr
Let +d+ = the distance in km the T to O train travels until they meet
+350+-+d+ = the distance in km the O to T train travels until they meet
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Equation for T to O train:
(1) +d+=+s%2A2.5+
Eqation for O to T train:
(2) +350+-+d+=+%28+s+%2B+10+%29%2A2.5+
----------------------------
Substitute (1) into (2)
(2) +350+-+2.5s+=+%28+s+%2B+10+%29%2A2.5+
(2) +350+-+2.5s+=+2.5s+%2B+25+
(2) +5s+=+325+
(2) +s+=+65+
and
+s+%2B+10+=+75+
----------------------
The T to O train travels 65 km/hr
The O to T train travels 75 km/hr
--------------------------------
check:
(1) +d+=+s%2A2.5+
(1) +d+=+65%2A2.5+
(1) +d+=+162.5+
and
(2) ++350+-+d+=+%28+s+%2B+10+%29%2A2.5+
(2) ++350+-+d+=+75%2A2.5+
(2) +d+=+350+-+187.5+
(2) +d+=+162.5+
OK

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
Toronto data
speed r
time 2.5
distance speed 2.5r
Ottawa
speed r%2B10
time 2.5
distance r%2B10*2.5
we know total distance is 350
2.5r+ r%2B10*2.5=350

r=65 km/h for toronto
for ottawa r%2B10 which is 65%2B10 equals 75km/h