SOLUTION: Jack cycled from A to B at an average speed of 20km/h. He then cycled back from B to A at an average speed of 18km/h. If he took a total of 1 hour 35 minutes, find the distance bet
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Question 1050730: Jack cycled from A to B at an average speed of 20km/h. He then cycled back from B to A at an average speed of 18km/h. If he took a total of 1 hour 35 minutes, find the distance between A and B? Found 2 solutions by jorel555, advanced_Learner:Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! First, 1 hour,35 minutes equals 1-35/60 hours, or 1-7/12 hours, equaling 19/12 hours total. Let n be the amount of time for the trip from A to B. Then:
20n=18(19/12-n)
20n=342/12-18n
38n=57/2
n=57/76
20 km/h x (57/76)hrs. =15 kilometers between A and B. ☺☺☺☺
You can put this solution on YOUR website! Jack cycled from A to B at an average speed of 20km/h. He then cycled back from B to A at an average speed of 18km/h. If he took a total of 1 hour 35 minutes, find the distance between A and B?
Cycle
speed 20
time t
distance 20t
cycle back
speed 18
time 19/12-t
distance 18(19/12-t)
20t=18(19/12-t)
20t=(3*19)/2-18t
t=(3*19)/2
t=
now calculate the distance
20(57/76)=distance
15km=Distance
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