SOLUTION: The numbers 1, 3, 4, 6 and 8 are placed in boxes A, B, C, D, and E so that the resulting product of the 2- and 3-digit numbers below is between 23000 and 25000. What is the largest

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Question 1050643: The numbers 1, 3, 4, 6 and 8 are placed in boxes A, B, C, D, and E so that the resulting product of the 2- and 3-digit numbers below is between 23000 and 25000. What is the largest possible value of the 2-digit number AB?
AB x CDE

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

Since we are trying to make AB large as possible, 
we first see if A can be 8.  So let's see what
happens when we assume A = 8.

   81+%3C=+AB+%3C=+86

But 

23000+%3C=+AB%2ACDE+%3C=+25000

23000%2FCDE+%3C=+AB+%3C=+25000%2FCDE

Then 23000%2FCDE%3E=81 and 25000%2FCDE%3C=86
     23000%3E=81%2ACDE and 25000%3C=86%2ACDE
     %22283.9...%22%3E=CDE and %22290.6...%22%3C=CDE

That's not possible.  

So A cannot be 8.

So we try A=6
    
We see if it is possible to make AB as large as possible
by making B=8

Then 68%2ACDE+%3E=+23000
     CDE+%3E=+%22338.2...%22

We can do that only by making CDE = 341

Answer:  68%2A341+=+23188, so the largest possible 
         value for AB is 68.

Edwin