i + 1 = = . Now apply de Moivre's formula: = . You will get = = = . (1) Similarly, i - 1 = = . = = = . (2) Combining (1) and (2), you will get (i+1)^3200-(i-1)^3200 = - = 0. Answer. (i+1)^3200-(i-1)^3200 = 0.