SOLUTION: find the dimensions of a rectangle having the least possible perimeter when its base and height are integers and its area is 18 centimeters squared.

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Question 1050400: find the dimensions of a rectangle having the least possible perimeter when its base and height are integers and its area is 18 centimeters squared.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x length of the rectangle, in cm
y = width of the rectangle, in cm
xy=18
18=2%5Ered%281%29%2A3%5Egreen%282%29 , so 18 has %28red%281%29%2B1%29%2A%28green%282%29%2B1%29=2%2A3=6 factors.
Those factors form 6%2F2=3 pairs of factors whose product is 18 .
The pairs/products are:
1%2A18=18 ,
2%2A9=18 , and
3%2A6=18 .
The perimeter of the rectangle is
2%28x%2By%29 .
If system%28x=18%2Cy=1%29 , perimeter=2%2A%281%2B18%29=2%2A19=38 .
If system%28x=9%2Cy=2%29 , perimeter=2%2A%282%2B9%29=2%2A11=22 .
If system%28x=6%2Cy=3%29 , perimeter=2%2A%283%2B6%29=2%2A9=highlight%2818%29 .