SOLUTION: Joseph invests $5100 in two different accounts. The first account paid 9 %, the second account paid 3 % in interest. At the end of the first year he had earned $243 in interest. Ho

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Joseph invests $5100 in two different accounts. The first account paid 9 %, the second account paid 3 % in interest. At the end of the first year he had earned $243 in interest. Ho      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1050370: Joseph invests $5100 in two different accounts. The first account paid 9 %, the second account paid 3 % in interest. At the end of the first year he had earned $243 in interest. How much was in each account?
Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
0.09x+(5100-x)*0.03=243
9x+(15300-3x)=24300
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=1500.
  • Graphical form: Equation 9x%2B15300-3x=24300 was fully solved.
  • Text form: 9x+15300-3x=24300 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+9x%2B15300-3x=24300+%29
    For tutors: simplify_cartoon( 9x+15300-3x=24300 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at 9%2Ax%2Bhighlight_red%28+15300+%29-3%2Ax=24300.
Moved 15300 to the right of expression
It becomes 9%2Ax-3%2Ax%2Bhighlight_green%28+15300+%29=24300.
Look at highlight_red%28+9%2Ax+%29-highlight_red%28+3%2Ax+%29%2B15300=24300.
Eliminated similar terms highlight_red%28+9%2Ax+%29,highlight_red%28+-3%2Ax+%29 replacing them with highlight_green%28+%289-3%29%2Ax+%29
It becomes highlight_green%28+%289-3%29%2Ax+%29%2B15300=24300.
Look at %28highlight_red%28+9+%29-highlight_red%28+3+%29%29%2Ax%2B15300=24300.
Added fractions or integers together
It becomes %28highlight_green%28+6+%29%29%2Ax%2B15300=24300.
Look at highlight_red%28+%28highlight_red%28+6+%29%29%2Ax+%29%2B15300=24300.
Remove unneeded parentheses around factor highlight_red%28+6+%29
It becomes highlight_green%28+6+%29%2Ax%2B15300=24300.
Look at 6%2Ax%2B15300=highlight_red%28+24300+%29.
Moved these terms to the left highlight_green%28+-24300+%29
It becomes 6%2Ax%2B15300-highlight_green%28+24300+%29=0.
Look at 6%2Ax%2Bhighlight_red%28+15300+%29-highlight_red%28+24300+%29=0.
Added fractions or integers together
It becomes 6%2Ax%2Bhighlight_green%28+-9000+%29=0.
Look at 6%2Ax%2Bhighlight_red%28+-9000+%29=0.
Removed extra sign in front of -9000
It becomes 6%2Ax-highlight_green%28+9000+%29=0.
Look at highlight_red%28+6%2Ax-9000+%29=0.
Solved linear equation highlight_red%28+6%2Ax-9000=0+%29 equivalent to 6*x-9000 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: x=1500.

Universal Simplifier and Solver


Done!