SOLUTION: Find three consecutive even integers such that twice the sum of the second and third is 36 more than the first

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Question 1050363: Find three consecutive even integers such that twice the sum of the second and third is 36 more than the first
Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive even integers such that twice the sum of the second and third is 36 more than the first



x
x+2
x+4

2*(2x+6)=x+36
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=8.
  • Graphical form: Equation 3x%2B12=36 was fully solved.
  • Text form: 3x+12=36 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+3x%2B12=36+%29
    For tutors: simplify_cartoon( 3x+12=36 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at 3%2Ax%2B12=highlight_red%28+36+%29.
Moved these terms to the left highlight_green%28+-36+%29
It becomes 3%2Ax%2B12-highlight_green%28+36+%29=0.
Look at 3%2Ax%2Bhighlight_red%28+12+%29-highlight_red%28+36+%29=0.
Added fractions or integers together
It becomes 3%2Ax%2Bhighlight_green%28+-24+%29=0.
Look at 3%2Ax%2Bhighlight_red%28+-24+%29=0.
Removed extra sign in front of -24
It becomes 3%2Ax-highlight_green%28+24+%29=0.
Look at highlight_red%28+3%2Ax-24+%29=0.
Solved linear equation highlight_red%28+3%2Ax-24=0+%29 equivalent to 3*x-24 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: x=8.

Universal Simplifier and Solver


Done!