SOLUTION: I need help with this system of equations the substitution method
Here's the problem: 2x+10y=4 and x=8-5y and I substituted the x=8-5y in for x and I got 2(8-5y)+10y=4 then I did
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-> SOLUTION: I need help with this system of equations the substitution method
Here's the problem: 2x+10y=4 and x=8-5y and I substituted the x=8-5y in for x and I got 2(8-5y)+10y=4 then I did
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Question 1050333: I need help with this system of equations the substitution method
Here's the problem: 2x+10y=4 and x=8-5y and I substituted the x=8-5y in for x and I got 2(8-5y)+10y=4 then I did the distributing and got 16-10y+10y=4 which I discovered was 0 after i combined them. And now I'm not sure where to go from here. So if you can please help me. Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! You went through the process of trying to solve and you found a false statement. GOOD. Now, look at the slopes of the two given equations!
, slope is . , slope is .
How would you know those/or that slope?
Solve for y in terms of x and look at the form y=mx+b.
The slope is the value of m.
So the two given lines have the same slope.
What does that tell you?
--
Parallel lines have no point in common, or in other words, they do not intersect.
You can put this solution on YOUR website!
I need help with this system of equations the substitution method
Here's the problem: 2x+10y=4 and x=8-5y and I substituted the x=8-5y in for x and I got 2(8-5y)+10y=4 then I did the distributing and got 16-10y+10y=4 which I discovered was 0 after i combined them. And now I'm not sure where to go from here. So if you can please help me.
Continue to get: - 10y + 10y = 4 - 16
Now, , and therefore, this system has NO SOLUTIONS, which indicates that the lines are parallel.
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