SOLUTION: passing through the midpoint of the line joining the points (4,0) and (5,3) and parallel to the line y = (5/7)x + 14

Algebra ->  Coordinate-system -> SOLUTION: passing through the midpoint of the line joining the points (4,0) and (5,3) and parallel to the line y = (5/7)x + 14      Log On


   

Question 1050276: passing through the midpoint of the line joining the points (4,0) and (5,3) and parallel to the line y = (5/7)x + 14
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
(4,0) and
(5,3) M(9/2, 3/2) Midpoint Pt(x,y): ( %28x%5B1%5D+%2B+x%5B2%5D%29%2F2, %28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29)
Parallel to y = (5/7)x + 14
m = (5/7)
y+-+3%2F2+=+%285%2F7%29%28x-9%2F2%29
y = (5/7)x -45/14 + 3/2
y = (5/7)x -45/14 + 21/14
y = (5/7)x -24/14
y = (5/7)x -12/7
Standard Form
5x - 7y = 12