SOLUTION: The sum of Teresa's and Cathy's weight is 118 pounds. Teresa weighs 26 pounds more than Cathy. If Teresa's weight is T and Cathy's weight is C, write and solve a system of equatio

Algebra ->  Equations -> SOLUTION: The sum of Teresa's and Cathy's weight is 118 pounds. Teresa weighs 26 pounds more than Cathy. If Teresa's weight is T and Cathy's weight is C, write and solve a system of equatio      Log On


   

Question 1050220: The sum of Teresa's and Cathy's weight is 118 pounds. Teresa weighs 26 pounds more than Cathy. If Teresa's weight is T and Cathy's weight is C, write and solve a system of equations to represent this scenario.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%28C%2BT=118%2CT=C%2B26%29-------------This is literally according to the description.

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system%28C=46%2CT=72%29

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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The sum of Teresa's and Cathy's weight is 118 pounds. Teresa weighs 26 pounds more than Cathy. If Teresa's weight is T and Cathy's weight is C, write and solve a system of equations to represent this scenario.
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T + C = 118,   (1)
T - C =  26.   (2)

When you see two equations like these (1) and (2), ADD them immediately.

By doing it, you get

2T = 118 + 26 = 144.  Hence T = 144%2F2 = 72. It is Teresa weight, in pounds.

Knowing it, you can find Cathy's weight from (1):

C = 118 - T = 118 - 72 = 46 pounds.

Answer.  Teresa weight is 72 pounds.  Cathy's weight is 46 pounds.

Solved.