SOLUTION: A pile of 34 coins is worth $5.10. There are two nickels and the remainder are quarters and dimes. How many quarters and dimes are there?

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Question 1050202: A pile of 34 coins is worth $5.10. There are two nickels and the remainder are quarters and dimes. How many quarters and dimes are there?
Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
q+d=32
10d+25q=510-10
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++1%5Cq+%2B+1%5Cd+=+32%2C%0D%0A++++10%5Cq+%2B+25%5Cd+=+500+%29%0D%0A++We'll use substitution. After moving 1*d to the right, we get:
1%2Aq+=+32+-+1%2Ad, or q+=+32%2F1+-+1%2Ad%2F1. Substitute that
into another equation:
10%2A%2832%2F1+-+1%2Ad%2F1%29+%2B+25%5Cd+=+500 and simplify: So, we know that d=12. Since q+=+32%2F1+-+1%2Ad%2F1, q=20.

Answer: system%28+q=20%2C+d=12+%29.