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| Question 1050139:   Alerts restaurant size can of soup is cylindrical with a diameter of 22 cm and a height of 28 cm .  This large can of soup will be used to feel small cylindrical bowls.  H small Super Bowl has a diameter of 15 cm and will be filled to a depth of 6 cm .  Turman how many centrical bulls can be filled with the amount of soup contained in the large can.
 Answer by addingup(3677)
      (Show Source): 
You can put this solution on YOUR website! So the large cylindrical can has: Diameter 22 means the radius is 22/2= 11
 Height 28
 Area of the base:
 A = Pi*r^2*height
 A = Pi*11^2*28
 A = 380.13*28 = 10,643.72
 And you want to fill: small cans with a diameter of  15 = radius 15/2 = 7.5 to a depth of 6.
 Follow the formula above:
 A = Pi*7.5^2*6 = 1,060.29
 Let's put it together, you can fill:
 10,643.72/1,060.29 = 10 cans (comes out to 10.038 due to rounding of decimals, it's 10 cans).
 
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