SOLUTION: A farmer has 100 acres of land for wheat or veg. Each acre of wheat yields €400 and each acre of veg yields €500. He makes €42,000 . How many acres of crops did he sow ?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: A farmer has 100 acres of land for wheat or veg. Each acre of wheat yields €400 and each acre of veg yields €500. He makes €42,000 . How many acres of crops did he sow ?      Log On


   



Question 1050126: A farmer has 100 acres of land for wheat or veg. Each acre of wheat yields €400 and each acre of veg yields €500. He makes €42,000 . How many acres of crops did he sow ?
Found 2 solutions by ikleyn, advanced_Learner:
Answer by ikleyn(52874) About Me  (Show Source):
You can put this solution on YOUR website!
.
A farmer has 100 acres of land for wheat or veg. Each acre of wheat yields €400 and each acre of veg yields €500. He makes €42,000 . How many acres of crops did he sow ?
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400x + 500*(400-x) = 42000.


One equation for one unknown. Simplify and solve for x, area for wheat in acres.


Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
x%2By=100
400x%2B500y=42000
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
We'll use substitution. After moving 1*y to the right, we get:
1%2Ax+=+100+-+1%2Ay, or x+=+100%2F1+-+1%2Ay%2F1. Substitute that
into another equation:
400%2A%28100%2F1+-+1%2Ay%2F1%29+%2B+500%5Cy+=+42000 and simplify: So, we know that y=20. Since x+=+100%2F1+-+1%2Ay%2F1, x=80.

Answer: system%28+x=80%2C+y=20+%29.


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