SOLUTION: I am thinking of two numbers. The sum of the first and twice the second is 34. The difference of the first and four times the second is 4. What are the numbers?

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Question 1050121: I am thinking of two numbers. The sum of the first and twice the second is 34. The difference of the first and four times the second is 4. What are the numbers?
Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=34
x-4y=4
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+34%2C%0D%0A++++1%5Cx+%2B+-4%5Cy+=+4+%29%0D%0A++We'll use substitution. After moving 1*y to the right, we get:
1%2Ax+=+34+-+1%2Ay, or x+=+34%2F1+-+1%2Ay%2F1. Substitute that
into another equation:
1%2A%2834%2F1+-+1%2Ay%2F1%29+%2B+-4%5Cy+=+4 and simplify: So, we know that y=6. Since x+=+34%2F1+-+1%2Ay%2F1, x=28.

Answer: system%28+x=28%2C+y=6+%29.