SOLUTION: Nadine has seven more nickels than Delano has dimes. If Delano gives Nadine four of his dimes, then delano will have the same amount of money as Nadine. How much money do they have
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Nadine has seven more nickels than Delano has dimes. If Delano gives Nadine four of his dimes, then delano will have the same amount of money as Nadine. How much money do they have
Log On
Question 1049978: Nadine has seven more nickels than Delano has dimes. If Delano gives Nadine four of his dimes, then delano will have the same amount of money as Nadine. How much money do they have together? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Nadine has seven more nickels than Delano has dimes.
If Delano gives Nadine four of his dimes, then delano will have the same amount of money as Nadine.
How much money do they have together?
:
let n = no. of nickels
let d = no. of dimes
:
Write an equation for each statement
:
" Nadine has seven more nickels than Delano has dimes."
n = d + 7
:
"If Delano gives Nadine four of his dimes, then delano will have the same amount of money as Nadine."
4 dimes = .40
.10d - .40 = .05n + .40
.10d = .05n + .40 + .40
.10d = .05n + .80
Replace n with (d+7) from the 1st statement
.10d = .05(d+7) + .80
.10d = .05d + .35 + .80
.10d - .05d = 1.15
.05d = 1.15
d = 1.15/.05
d = 23 dimes originally
then
n = 23 + 7
n = 30 nickels
:
See if that checks out
.10(23) - .40 = .05(30) + .40
2.30 - .40 = 1.50 + .40
1.90 = 1.90
:
How much money do they have together?
23(.10) + 30(.05) =
2.30 + 1.50 = $3.80
