SOLUTION: Find two consecutive even integers such that the sum of twice the lesser and three times the greater is 66.

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Question 1049905: Find two consecutive even integers such that the sum of twice the lesser and three times the greater is 66.
Found 2 solutions by ewatrrr, MathLover1:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
two consecutive even integers: x and (x+2)
2x + 3(x+2) = 66
5x = 60
x = 12
The two consecutive even integers are: 12 , 14
AND
24 + 42 = 66 CHECKS!


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Lets call the first integer x.
For the second integer to be a consecutive even interger it must be x%2B2}
so far we have:
first interger = x
second interger = x%2B2
if given that the sum of twice the lesser and three times the greater is 66, we have
2x%2B3%28x%2B2%29=66...............solve for x
2x%2B3x%2B6=66
5x=66-6
5x=60
x=60%2F5
x=12
and, second one is x%2B2=14