SOLUTION: Nancy has $4.80 in change. She has three times as many nickles as quarters. She has two more quarters than dimes. How many coins of each type does she have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Nancy has $4.80 in change. She has three times as many nickles as quarters. She has two more quarters than dimes. How many coins of each type does she have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1049894: Nancy has $4.80 in change. She has three times as many nickles as quarters. She has two more quarters than dimes. How many coins of each type does she have?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Let x represent number of Quarters:
25x + 10(x-2) + 5(3x) = 480 CENTS make sense
50x - 20 = 480
50x = 500
x = 10, number of Quarters. Dimes 8, Nickels 30
AND Checking
250 + 80 + 150 = 480 CHECKS!