The solution above is incorrect!
If z = 214∙320, what is the largest
power of 12 that evenly divides into the square root of z?


Let p = the largest power of 12 that evenly divides into the
square root of z




We are given:


We find the square root of z




Now we divide
INTO
, which amounts to
dividing
BY


Subtracting exponents on the right


Negative exponents cause denominators. Therefore both those
exponents must be non-negative (greater than or equal to zero)
in order for the above result to be an integer, so we have:


and 



and 

Remember that the inequality reverses when dividing
by a negative number:


and 



and 



and 

The largest integer value of p that satisfies both those is p = 3.
Answer: The largest power of 12 that evenly divides into the square
root of z is 3.
Edwin