SOLUTION: Find f' (x) given f(x) as follows. f(x) = (x^3 + 2x^2 + 5)^5
Algebra
->
Geometry-proofs
-> SOLUTION: Find f' (x) given f(x) as follows. f(x) = (x^3 + 2x^2 + 5)^5
Log On
Geometry: Proofs in Geometry
Geometry
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Geometry proofs
Question 1049875
:
Find f' (x) given f(x) as follows.
f(x) = (x^3 + 2x^2 + 5)^5
Answer by
ewatrrr(24785)
(
Show Source
):
You can
put this solution on YOUR website!
f(x) = (x^3 + 2x^2 + 5)^5
f' = 5(3x^2 + 4x)(x^3 + 2x^2 + 5)^4
f' = 5x(3x + 4)(x^3 + 2x^2 + 5)^4