Question 1049742: f(x)=1/1-x
find:
1.f'(0)
2.f"(0)
3.f"'(0)
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! Using the Division Rule:
f = 1/(1-x)
1) f' = [0 - 1(-1)]/(1-x)^2 = 1/(1-x)^2 , f'(0) = 1
2) f" = [0 - (-1)2(1-x)]/(1-x)^4 = -2(1-x)/ (1-x)^4 = -2/(1-x)^3 , f"(0) = -2
3) f'" = [0 - (-2)3(1-x)^2]/(1-x)^6 = -6(1-x)^2/ (1-x)^6 = -6/(1-x)^4, f"'(0) = -6
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