SOLUTION: a cylclist travled 9km per hour faster than an in line skater. in the time it took the cyclist to travel 45 km, the skater had gone 30. find the speed of the skater

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Question 1049609: a cylclist travled 9km per hour faster than an in line skater. in the time it took the cyclist to travel 45 km, the skater had gone 30. find the speed of the skater
Found 2 solutions by stanbon, advanced_Learner:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
: a cyclist travled 9km per hour faster than an in line skater. in the time it took the cyclist to travel 45 km, the skater had gone 30. find the speed of the skater
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Cyclist DATA:
rate = x+9 km/h ; dist = 45 km ; time = d/r = 45/(x+9) hrs
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Skater DATA:
rate = x km/h ; dist = 30 km ; time = d/r = 30/x
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Equation:
45/(x+9) = 30/x
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45x = 30x + 270
15x = 270
x = 18 km/hr (skater rate)
x+9 27 km/hr (cyclist rate)
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Cheers,
Stan H.
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Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
line skater
speed r
time t
distance 30
30=rt
30%2F%28r%29=t
cyclist
speed r%2B9
time t
distance 45
30/r=t
45/r%2B9=t
30%2F%28r%29=45/r%2B9
r%2F%2830%29=r%2B9/45
45r=30r%2B270
45r-30r=270
15r=270
r=18
hence for the line skater
r=18
for the cyclist
r=18%2B9
r=27