SOLUTION: A punter kicks a football. Its height, h(t), in meters t seconds after the kick is given by the equation h(t)= -4.9t^2 + 18.24t + 0.8. The height of an approaching blocker's hands
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-> SOLUTION: A punter kicks a football. Its height, h(t), in meters t seconds after the kick is given by the equation h(t)= -4.9t^2 + 18.24t + 0.8. The height of an approaching blocker's hands
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Question 1049513: A punter kicks a football. Its height, h(t), in meters t seconds after the kick is given by the equation h(t)= -4.9t^2 + 18.24t + 0.8. The height of an approaching blocker's hands is modelled by the equation g(t)= -1.43t + 4.26. Can the blocker knock down the punt? If so what point will it happen? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! -4.9t^2 + 18.24t + 0.8 = -1.43t + 4.26
-4.9t^2 + 19.67t - 3.46
t = .18 0r t= 3.83
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t = .18
g(.18) ~4m
