SOLUTION: Find a cubic polynomial with zeros: 2, {{{sqrt (2)}}} ,{{{ -sqrt (2)}}} I am thinking that I need to work the problem backwards but i'm not sure where to get started. I began th

Algebra ->  Trigonometry-basics -> SOLUTION: Find a cubic polynomial with zeros: 2, {{{sqrt (2)}}} ,{{{ -sqrt (2)}}} I am thinking that I need to work the problem backwards but i'm not sure where to get started. I began th      Log On


   

Question 1049505: Find a cubic polynomial with zeros: 2, sqrt+%282%29 ,+-sqrt+%282%29
I am thinking that I need to work the problem backwards but i'm not sure where to get started. I began thinking that perhaps I need to do the following:
(x-2)%28x-sqrt%282%29%29 %28x%2Bsqrt%282%29%29
and multiply these three factors together?
Answer by Edwin McCravy(20063) About Me  (Show Source):
You can put this solution on YOUR website!
(x-2)%28x-sqrt%282%29%29 %28x%2Bsqrt%282%29%29

Yes multiply them all together

%28x-2%29%28x-sqrt%282%29%29%28x%2Bsqrt%282%29%29

It will be lots easier if you multiply the 2nd and 3rd 
parentheses together first and simplify, because the 
terms with square root will cancel out.  Then multiply
the (x-2) by what you get.

Edwin