SOLUTION: Determine the domain of h(x) = 5/ sqrt 2x+10 and write it using set builder notation.

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Question 1049503: Determine the domain of h(x) = 5/ sqrt 2x+10 and write it using set builder notation.
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
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h%28x%29+=+5%2F+%28sqrt+%282x%2B10+%29%29 in a domain will be all values of x except the value that makes sqrt+%282x%2B10+%29 equal to zero and that is
sqrt+%282x%2B10+%29=0
2x%2B10+=0
2x=-10
x=-10%2F2
x=-5

so, we will exclude -5 and domain is: { x element R : x%3C%3E-5 }


Answer by ikleyn(52903) About Me  (Show Source):
You can put this solution on YOUR website!
.
Determine the domain of h(x) = 5/ sqrt 2x+10 and write it using set builder notation.
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The domain of  h(x) = 5%2Fsqrt%282x%2B10%29  is  {x of R | x > -5},  or, which is the same,  (-5,infinity).


The condition to determine the domain is  2x + 10 > 0.