SOLUTION: Given: ∠A is comp. to ∠B ∠C is comp. to ∠B ∠A = (3x+y)° ∠B = (x+4y+2)° ∠C = (3y-3)° Find: m∠B (comp. = complementary) I w

Algebra ->  Angles -> SOLUTION: Given: ∠A is comp. to ∠B ∠C is comp. to ∠B ∠A = (3x+y)° ∠B = (x+4y+2)° ∠C = (3y-3)° Find: m∠B (comp. = complementary) I w      Log On


   

Question 1049483: Given: ∠A is comp. to ∠B
∠C is comp. to ∠B
∠A = (3x+y)°
∠B = (x+4y+2)°
∠C = (3y-3)°
Find: m∠B
(comp. = complementary)
I was thinking that since complementary angles are (90-x) you would figure out what x is by possibly adding angle A angle B and angle C all together and solving... I'm not sure if this is right. Would you use solving systems? I was thinking maybe you would because there's x and y you need to solve for. I am having a hard time understanding this concept.
Found 3 solutions by ikleyn, advanced_Learner, hussamuddin:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
Your thinking is correct.

Go farther ahead!


Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
the equations+ are

A%2BB=90 eq 1
B%2BC=90 eq 2
3x%2By%2Bx%2B4y%2B2=90 eq 1
x%2B4y%2B2%2B3y-3=90 eq 2
4x%2B5y=88 eq 1
x%2B7y=91 eq 2
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++4%5Cx+%2B+5%5Cy+=+88%2C%0D%0A++++1%5Cx+%2B+7%5Cy+=+91+%29%0D%0A++We'll use substitution. After moving 5*y to the right, we get:
4%2Ax+=+88+-+5%2Ay, or x+=+88%2F4+-+5%2Ay%2F4. Substitute that
into another equation:
1%2A%2888%2F4+-+5%2Ay%2F4%29+%2B+7%5Cy+=+91 and simplify: So, we know that y=12. Since x+=+88%2F4+-+5%2Ay%2F4, x=7.

Answer: system%28+x=7%2C+y=12+%29.

Answer by hussamuddin(51) About Me  (Show Source):
You can put this solution on YOUR website!
you are right, go ahead