SOLUTION: Dan left school and drove east on Mass Pike at 55 mph. One hour later, Joe left school and traveled west on the Mass Pike at 50 miles per hour. How long will Dan have traveled when
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Question 1049380: Dan left school and drove east on Mass Pike at 55 mph. One hour later, Joe left school and traveled west on the Mass Pike at 50 miles per hour. How long will Dan have traveled when he and Joe are 300 miles apart? Found 2 solutions by addingup, advanced_Learner:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! 55(x+1)+50x = 300
55x+55+50x = 300
105x = 245
x = 245/105 = 2.33 hours or 0.3333*60 = 20 thus 2 hours and 20 minutes
Note: There are 60 minutes in an hour, this is why 0.3333 of an hour times 60
Cartoon (animation) form: For tutors: simplify_cartoon( 105t=245 )
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DETAILED EXPLANATION
Look at . Moved these terms to the left It becomes . Look at . Solved linear equation equivalent to 105*t-245 =0 It becomes . Result: This is an equation! Solutions: t=2.33333333333333.
