SOLUTION: Make sure to superscript all exponents. All exponents in final answers should be positive. Final answers should have all single connecting signs and be arranged in descending ord

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Make sure to superscript all exponents. All exponents in final answers should be positive. Final answers should have all single connecting signs and be arranged in descending ord      Log On


   

Question 104925: Make sure to superscript all exponents. All exponents in final answers should be positive. Final answers should have all single connecting signs and be arranged in descending order.
1. Simplify and evaluate:
(x^4 y^6 z^12/9^-2 x^3 y^-8 z^-9)^0
I am confused on this one. Our seminars cover the previous week so we have to figure this out before we are taught. Thanks
Found 2 solutions by jim_thompson5910, Fombitz:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E4%2Ay%5E6%2Az%5E12%2F%289%5E-2%2Ax%5E3%2Ay%5E-8%2Az%5E-9%29%29%5E0 Start with the given expression


Let w=x%5E4%2Ay%5E6%2Az%5E12%2F%289%5E-2%2Ax%5E3%2Ay%5E-8%2Az%5E-9%29


w%5E0 Now replace the entire expression inside the parenthesis with w


Remember anything to the zeroth power (except zero) is one. So w%5E0=1. This means the whole expression raised to the zeroth power is one. So even though it looks really complicated, the answer is really simple.



So %28x%5E4%2Ay%5E6%2Az%5E12%2F%289%5E-2%2Ax%5E3%2Ay%5E-8%2Az%5E-9%29%29%5E0=1

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Seems like a lot of smokescreening in the instructions.
The entire problem hinges on that last exponent.
u%5E0=1 Independent of what value u has.