SOLUTION: Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t) = 2.6667t^2, where t is in seconds and d(t) is in feet. If an object is d
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-> SOLUTION: Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t) = 2.6667t^2, where t is in seconds and d(t) is in feet. If an object is d
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Question 1049228: Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t) = 2.6667t^2, where t is in seconds and d(t) is in feet. If an object is dropped from a certain height, find the average speed of the object from t = 1 to t = 4. Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! d = r*t so r = d/t
d(1) = 2.6667(1)^2
d(1) = 2.6667
r = 2.6667/1 = 2.6667 is the speed, and in this case, where t=1, it is also the distance traveled in 1 second
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d(4) = 2.6667(4)^2
d(4) = 2.6667*16 = 42.6672 is the distance traveled in 4 seconds
r = 42.6672/4 = 10.6668 is the speed per second
