Question 1049065: A girl invested $10,000 for one year, part at 8% annual interest and the rest at 12% annual interest. her total interest for the year was $944. how much money did she invest at each rate?
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Part at 8% = x
Rest at 12% = 10,000-x, since x is invested at 8%
0.08x+0.12(10,000-x) = 944
0.08x+1200-0.12x = 944 subtract 1200 from both sides
0.08-0.12 = -256 Subtract on left
-0.04x = -256 Divide both sides by -0.12 and remember -/- = +
x = 6,400 this is how much is invested at 8%, and:
10,000-6,400 = 3,600 is invested at 12%
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