SOLUTION: Rewrite the following logarithmic equation in exponential form. a) log (m) = n b) log3 (81) = 4 c) logsqrt[5] (5) = 2 d) log3/4 (64/27) = -3 e) log4 (2) = 1/2 f) log10

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Rewrite the following logarithmic equation in exponential form. a) log (m) = n b) log3 (81) = 4 c) logsqrt[5] (5) = 2 d) log3/4 (64/27) = -3 e) log4 (2) = 1/2 f) log10       Log On


   



Question 1048973: Rewrite the following logarithmic equation in exponential form.
a) log (m) = n
b) log3 (81) = 4
c) logsqrt[5] (5) = 2
d) log3/4 (64/27) = -3
e) log4 (2) = 1/2
f) log10 (0.001) = -3
g) ln8 = 9
h) ln5 = a

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Rewrite the following logarithmic equation in exponential form.
The log is the exponent. Remember that.
I'll do some, you do the rest.
email via the TY note for help or to check your work.
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a) log (m) = n
The log is n, that's the exponent.
It's the based raised to the exponent.
--> m = 10^n
========================
b) log3 (81) = 4
---
c) log(sqrt[5] (5)) = 2
%28sqrt%285%29%29%5E2+=+5
====================
d) log3/4 (64/27) = -3
%283%2F4%29%5E%28-3%29+=+64%2F27
=====================
e) log4 (2) = 1/2
f) log10 (0.001) = -3
-------------
g) ln8 = 9
e%5E9+=+8
********** this is not true. Should not be included.
====================
h) ln5 = a
a is the exponent, e is the base.
e^a = 5
PS Use parentheses.
ln(5) = a
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